Fungsi dénsitas probabilitas: Béda antarrépisi

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for any two numbers ''a'' and ''b''. This implies that the total integral of ''f'' must be 1. Conversely, any non-negative Lebesgue-integrable function with total integral 1 is the probability density of a suitably defined probability distribution.
for any two numbers ''a'' and ''b''. This implies that the total integral of ''f'' must be 1. Conversely, any non-negative Lebesgue-integrable function with total integral 1 is the probability density of a suitably defined probability distribution.


For example, the uniform distribution on the interval [0,1] has probability density ''f''(''x'') = 1 for 0 ≤ ''x'' ≤ 1 and zero elsewhere. The standard [[normal distribution]] has probability density
Contona, sebaran seragam dina interval [0,1] ngabogaan probabiliti densiti ''f''(''x'') = 1 keur 0 ≤ ''x'' ≤ 1 jeung nol dimamana. Standar [[sebaran normal]] ngabogaan probabiliti densiti


:<math>f(x)={e^{-{x^2/2}}\over \sqrt{2\pi}}</math>.
:<math>f(x)={e^{-{x^2/2}}\over \sqrt{2\pi}}</math>.
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It is a common mistake to think of ''f''(''a'') as the probability of {''a''}, but this is incorrect; in fact, ''f''(''a'') will often be bigger than 1 - consider a random variable with a [[uniform distribution]] between 0 and 1/2.
It is a common mistake to think of ''f''(''a'') as the probability of {''a''}, but this is incorrect; in fact, ''f''(''a'') will often be bigger than 1 - consider a random variable with a [[uniform distribution]] between 0 and 1/2.


Two densities ''f'' and ''g'' for the same distribution can only differ on a set of [[Lebesgue measure]] zero.
Dua densiti ''f'' jeung ''g'' for the same distribution can only differ on a set of [[Lebesgue measure]] zero.





Révisi nurutkeun 30 Agustus 2004 23.19


Dina matematik, probability density function dipake keur ngagambarkeun probability distribution di watesan integrals. Lamun probability distribution ngabogaan densiti f(x), saterusna interval tak terhingga [x, x + dx] ngabogaan probabiliti f(x) dx. Probability density function bisa oge ditempo tina versi "smoothed out" histogram: if one empirically measures values of a random variable repeatedly and produces a histogram depicting relative frequencies of output ranges, then this histogram will resemble the random variable's probability density (assuming that the variable is sampled sufficiently often and the output ranges are sufficiently narrow).

Formally, a probability distribution has density f(x) if f(x) is a non-negative Lebesgue-integrable function RR such that the probability of the interval [a, b] is given by

for any two numbers a and b. This implies that the total integral of f must be 1. Conversely, any non-negative Lebesgue-integrable function with total integral 1 is the probability density of a suitably defined probability distribution.

Contona, sebaran seragam dina interval [0,1] ngabogaan probabiliti densiti f(x) = 1 keur 0 ≤ x ≤ 1 jeung nol dimamana. Standar sebaran normal ngabogaan probabiliti densiti

.

If a random variable X is given and its distribution admits a probability density function f(x), then the expected value of X (if it exists) can be calculated as

Not every probability distribution has a density function: the distributions of discrete random variables do not; nor does the Cantor distribution, even though it has no discrete component, i.e., does not assign positive probability to any individual point.

A distribution has a density function if and only if its cumulative distribution function F(x) is absolutely continuous. In this case, F is almost everywhere differentiable, and its derivative can be used as probability density. If a probability distribution admits a density, then the probability of every one-point set {a} is zero.

It is a common mistake to think of f(a) as the probability of {a}, but this is incorrect; in fact, f(a) will often be bigger than 1 - consider a random variable with a uniform distribution between 0 and 1/2.

Dua densiti f jeung g for the same distribution can only differ on a set of Lebesgue measure zero.


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